Registry Query Batch

Hello,
I am new to the forum and  I was hoping that someone could help me figure this out.  I am not sure whether a for statement or an if/then/else statement should be used, but I am trying to write a batch file that I could reuse the code on when evaluating several areas of the registry through a batch file.  I would really only need one variable that was just set to something new each time it is come across in my batch file, but I was trying to take the value "MinimumPasswordAge" from "HKLM??\System\CurrentControlSet\Services\Netlogon\Parameters", assign it to a variable, and if the value was greater than or equal to 30, then it should echo Pass.  If it does not meet that criteria, then it should echo Fail and continue through the rest of the batch file.
 
I would appreciate any advice and help on this!
Thanks,
John

The problem is not pulling the value out of the registry--you can do that with a FOR statement...
 
for /f "tokens=3" %%a in ('reg query hklm\System\CurrentControlSet\Services\Netlogon\Parameters /v MinimumPasswordAge ^| find /i "MinimumPasswordAge"') do set MinimumPasswordAge=%%a
 
The problem is, the value is stored as hex in the registry and the IF does a decimal based comparison.  I'm not sure how to determine if the value of %MinimumPasswordAge% is greater than or equal to 1E.  Sorry if that's not much help.
 

I think I have it figured out because the IF statements allow me to test if the variable is less than or equal to hexadecimal.  I tried it several times without issue.  Now I ask, how would I write an if statement that says if a variable is less than or equal to 2 AND greater than or equal to 1?  Here is what I am trying to do, even though this syntax does not work...
 
IF %testvalue% LEQ 2 AND %testvalue% GEQ 1 (ECHO Pass) Else (ECHO Fail)
 
Any help would be greatly appreciated!

I don't believe that IF supports AND.  You may need to break it down...
 
if %testvalue% leq 2 (goto eval2) else (goto fail)
:eval2
if %testvalue% geq 1 (goto pass) else (goto fail)
:fail
echo fail
goto end
:pass
echo pass
:end

Thank you for responding, but I just figured it out.  I basically have this where I am checking to see if a registry value is set to 1 or 2, but nothing else.
 
for /f "tokens=3" %%a in ('reg query "HKLM\blah" /v RegValue" ^| find /i "RegValue"') do set leq2test=%%a
If %leq2test% LEQ 2 (set test1="Pass") ELSE (set test1="Fail")
?for /f "tokens=3" %%b in ('reg query "HKLM\blah" /v RegValue" ^| find /i "RegValue"') do set geq1test=%%b
If %geq1test% GEQ 1 (set test2="Pass") ELSE (set test2="Fail")
If test1 == test2 (Echo Pass) ELSE (Echo Fail)
 
It might not be the best way to do it, but it works!
Now I just need to figure out how to check to see if the Lockout Threshold is not 0, but less that 3.  I know that I can view it with the net accounts command, but dont know how to use it for this case.
 
Thanks!

Using variables as switches works too.  However, if "Fail"=="Fail", you'll still echo "Pass".  I realize that you can never have a scenario where X is not <= 2 and X is not >=1 but, if you use this logic with different test criteria, you may not receive the results you expect.  Also, since you are querying the registry twice for the same value, it may speed the batch file up a bit if you set a single variable for the lone registry value.  How about something like?...
 
for /l %%a in (1,1,2) do set test%%a=fail
for /f "tokens=3" %%a in ('reg query "hklm\blah" /v regvalue" ^| find /i "regvalue"') do set regvalue=%%a
if %regvalue% leq 2 set test1=pass
if %regvalue% geq 1 set test2=pass
if /i "%test1%%test2%"=="passpass" (echo pass) else (echo fail)